+/**
+ * \brief binary_write binary_write
+ * @param os ostream to write to
+ * @param val value
+ * @param len length of the 'value' to be written
+ */
+std::ostream &binary_write(std::ostream &os, const uint8_t *val, size_t len)
+{
+ // We are writting sizeof(char) thus no need to swap bytes
+ return os.write(reinterpret_cast<const char*>(val), len);
+}
+
+/**
+ * \brief binary_write binary_write
+ * @param os ostream to write to
+ * @param val val
+ * @param len length of the 'value' to be written
+ */
+std::ostream &binary_write(std::ostream &os, const uint16_t *val, size_t len)
+{
+// This is tricky since we are writting two bytes buffer.
+// Be carefull with little endian vs big endian.
+// Also this other trick is to allocate a small (efficient) buffer that store
+// intermediate result before writting it.
+#if defined(GDCM_WORDS_BIGENDIAN) || defined(GDCM_FORCE_BIGENDIAN_EMULATION)
+ const int BUFFER_SIZE = 4096;
+ static char buffer[BUFFER_SIZE];
+ uint16_t *binArea16 = (uint16_t*)val; //for the const
+
+ // how many BUFFER_SIZE long pieces in binArea ?
+ int nbPieces = len/BUFFER_SIZE; //(16 bits = 2 Bytes)
+ int remainingSize = len%BUFFER_SIZE;
+
+ for (int j=0;j<nbPieces;j++)
+ {
+ uint16_t *pbuffer = (uint16_t*)buffer; //reinitialize pbuffer
+ for (int i = 0; i < BUFFER_SIZE/2; i++)
+ {
+ *pbuffer = *binArea16 >> 8 | *binArea16 << 8;
+ pbuffer++;
+ binArea16++;
+ }
+ os.write ( buffer, BUFFER_SIZE );
+ }
+ if ( remainingSize > 0)
+ {
+ uint16_t *pbuffer = (uint16_t*)buffer; //reinitialize pbuffer
+ for (int i = 0; i < remainingSize/2; i++)
+ {
+ *pbuffer = *binArea16 >> 8 | *binArea16 << 8;
+ pbuffer++;
+ binArea16++;
+ }
+ os.write ( buffer, remainingSize );
+ }
+ return os;
+#else
+ return os.write(reinterpret_cast<const char*>(val), len);
+#endif
+}
+