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[CreaPhase.git] / octave_packages / m / time / eomday.m

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+## Copyright (C) 2004-2012 Paul Kienzle
+##
+## This file is part of Octave.
+##
+## Octave is free software; you can redistribute it and/or modify it
+## under the terms of the GNU General Public License as published by
+## the Free Software Foundation; either version 3 of the License, or (at
+## your option) any later version.
+##
+## Octave is distributed in the hope that it will be useful, but
+## WITHOUT ANY WARRANTY; without even the implied warranty of
+## MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
+## General Public License for more details.
+##
+## You should have received a copy of the GNU General Public License
+## along with Octave; see the file COPYING.  If not, see
+## <http://www.gnu.org/licenses/>.
+
+## -*- texinfo -*-
+## @deftypefn {Function File} {@var{e} =} eomday (@var{y}, @var{m})
+## Return the last day of the month @var{m} for the year @var{y}.
+## @seealso{weekday, datenum, datevec, is_leap_year, calendar}
+## @end deftypefn
+
+## Author: pkienzle <pkienzle@users.sf.net>
+## Created: 25 July 2004
+## Adapted-By: William Poetra Yoga Hadisoeseno <williampoetra@gmail.com>
+
+function e = eomday (y, m)
+
+  if (nargin != 2)
+    print_usage ();
+  endif
+
+  eom = [31, 28, 31, 30 ,31, 30, 31, 31, 30, 31, 30, 31];
+  e = reshape (eom(m), size (m));
+  e += (m == 2) & (mod (y, 4) == 0 & (mod (y, 100) != 0 | mod (y, 400) == 0));
+
+endfunction
+
+
+%!demo
+%! ## Find leap years in the 20th century
+%! y = 1900:1999;
+%! e = eomday (y, repmat (2, [1, 100]));
+%! y(find (e == 29))
+
+# tests
+%!assert (eomday ([-4:4],2), [29,28,28,28,29,28,28,28,29])
+%!assert (eomday ([-901,901],2), [28,28])
+%!assert (eomday ([-100,100],2), [28,28])
+%!assert (eomday ([-900,900],2), [28,28])
+%!assert (eomday ([-400,400],2), [29,29])
+%!assert (eomday ([-800,800],2), [29,29])
+%!assert (eomday (2001,1:12), [31,28,31,30,31,30,31,31,30,31,30,31])
+%!assert (eomday (1:3,1:3), [31,28,31])
+%!assert (eomday (1:2000,2)', datevec(datenum(1:2000,3,0))(:,3))
+%!assert ([1900:1999](find(eomday(1900:1999,2*ones(1,100))==29)), [1904,1908,1912,1916,1920,1924,1928,1932,1936,1940,1944,1948,1952,1956,1960,1964,1968,1972,1976,1980,1984,1988,1992,1996])
+%!assert (eomday ([2004;2005], [2;2]), [29;28])
+
+%% Test input validation
+%!error eomday ()
+%!error eomday (1)
+%!error eomday (1,2,3)
+